thermodynamics :

An idea gas undergoes a process in which its internal energy U is related to its volume U=aV^b ,where a,b are constants..Show that the work done by the gas and the quantity of heat transferred to it to increase its internal energy by $\delta$U are respectively.....(see in the comments)

Question

thermodynamics :

An idea gas undergoes a process in which its internal energy U is related to its volume U=aV^b ,where a,b are constants..Show that the work done by the gas and the quantity of heat transferred to it to increase its internal energy by $\delta$U are respectively.....(see in the comments)

souvik · Answer

1.$$\frac{ \Delta  U (\gamma-1)}{ b }$$
2.$$\frac{ \Delta U\{1+(\gamma-1)b\} }{ b }$$

souvik · Answer

the relation between U & V is$$U=aV ^{b}$$

souvik · Answer

@Vincent-Lyon.Fr

vincent-lyon.fr · Answer

Sorry, it must be quite simple, but I'm not getting through.

irishboy123 · Answer

.