Question

Which of the following is a possible set of quantum numbers for an electron n, l, m subscript l, m subscript s ?
A. (1, 1, 0, 1/2)
B. (2, 1, 1, 1/2)
C. (3, 2, 3, -1/2)
D. (3, -2, 1, -1/2)

Answer 1

Is this Apex chemistry?

Answer 2

no it's flvs

Answer 3

some pls help :/

Answer 4

N = principle quantum number, tells you your energy level.
L = shape that's the way I think of L
m = can be less than or equal to L, shows how many orientations the orbitals can have. Can't be greater than L
S = spin can either be +1/2 or -1/2 don't remember exactly.

Say if we have 2P

P orbitals have 3 possible orientations,

Px,Py,Pz

L = 1
M = +1 -1 0 corresponding to the Px,Py,Pz
You can have spin up or down

Answer 5

If we have l = 2

That means we can have

-2, -1, 0, 1, 2 which is five orientations

Two electrons for each orbital so that's 10 total. That would give us a D orbital.

a D orbital would have l = 2 and would start at principle quantum number of 3

Answer 6

You know that the spin can either be +1/2 or -1/2 so that won't tell you which one is right. So based off of what I said can you predict what the answer would be?