Question

For the quantum number lower case L = 0, how many possible values are there for the quantum number m subscrip l?
A. 0
B. 1
C. 2
D. 3

Answer 1

pls help

Answer 2

if \(l\) = 0
that means that your principle quantum number, \(n\)= 1
because \(l\) = \(n\) -1

and \(m\) can be any value from -\(l\) to +\(l\)
So if i have:

\(l\)= 2
\(m\) can be -2, -1, 0, +1, and +2
it's in that range!

Answer 3

thank you!!