Geometry problem that im a bit confused on. Using the law of sines, in triangle ABC, if m

Question

Geometry problem that im a bit confused on. Using the law of sines, in triangle ABC, if m<B=105 degrees, b=23, a=14, find m<A

tw101 · Answer

@ganeshie8

anonymous · Answer

So |dw:1436208788719:dw|

tw101 · Answer

okay, what would I do next?  i know the law of sines is Sin A/a=SinB/b=SinC/c, but when i substitute it all together it doesnt make sense to me.

anonymous · Answer

Just use the Law of sines ratio $$\large \frac{sin(105)}{23}~=~\frac{sin<a}{14}$$ Get <a alone

tw101 · Answer

okay so would I do the inverse of sin and multiply both sides by 14?

anonymous · Answer

Well let's do it one step at a time. First is to yes, multiply both sides by 14. Tell me what you get.

tw101 · Answer

sin (1470)/322

anonymous · Answer

It should look more like $$\large \frac{14 \times sin(105)}{23}$$

tw101 · Answer

oh okay. and then do I inverse both sides?

anonymous · Answer

Correct

anonymous · Answer

So $$\large <a~=~ asin \large( \normalsize \frac{14 \times sin(105)}{23} \large )$$

tw101 · Answer

okay i got 36.01

anonymous · Answer

That would be your answer :) good job

tw101 · Answer

thank you so much!

anonymous · Answer

$$\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile $$

tw101 · Answer

can i ask one more question?