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Mathematics 18 Online
OpenStudy (anonymous):

What is the standard form of the equation of a circle that has its center at (-2, -3) and passes through the point (-2, 0)? (x + 2)squared + (y + 3)squared = 9 (x − 2)squared + (y − 3)squared = 16 (x − 2)squared + (y − 3)squared = 4 (x + 2)squared + (y + 3)squared = 16 (x − 2)squared + (y + 3)squared = 9

OpenStudy (anonymous):

@LegendarySadist

OpenStudy (anonymous):

(-2,-3) and (-2,0) have the same x. So 0-(-3)=?

OpenStudy (anonymous):

3

OpenStudy (anonymous):

So there's your radius. Now just put the info into standard form. \[\large (x-h)^{2}~+~(y-k)^{2}=r^{2}\] \[\large (h,k)~=~Center~coordinates~of~circle\] \[\large r~=~radius\]

OpenStudy (anonymous):

either A or E right?

OpenStudy (anonymous):

Do you mean A or D?

OpenStudy (anonymous):

right x)

OpenStudy (anonymous):

it's D right?

OpenStudy (anonymous):

r=3. \(3^{2}=?\)

OpenStudy (anonymous):

9 so A! thanks!

OpenStudy (anonymous):

Right, A. And \[\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile \]

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