What is the standard form of the equation of a circle that has its center at (-2, -3) and passes through the point (-2, 0)? (x + 2)squared + (y + 3)squared = 9 (x − 2)squared + (y − 3)squared = 16 (x − 2)squared + (y − 3)squared = 4 (x + 2)squared + (y + 3)squared = 16 (x − 2)squared + (y + 3)squared = 9
@LegendarySadist
(-2,-3) and (-2,0) have the same x. So 0-(-3)=?
3
So there's your radius. Now just put the info into standard form. \[\large (x-h)^{2}~+~(y-k)^{2}=r^{2}\] \[\large (h,k)~=~Center~coordinates~of~circle\] \[\large r~=~radius\]
either A or E right?
Do you mean A or D?
right x)
it's D right?
r=3. \(3^{2}=?\)
9 so A! thanks!
Right, A. And \[\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile \]
Join our real-time social learning platform and learn together with your friends!