Question

What is the standard form of the equation of a circle that has its center at (-2, -3) and passes through the point (-2, 0)?
(x + 2)squared + (y + 3)squared = 9
(x − 2)squared + (y − 3)squared = 16
(x − 2)squared + (y − 3)squared = 4
(x + 2)squared + (y + 3)squared = 16
(x − 2)squared + (y + 3)squared = 9

Answer 1

@LegendarySadist

Answer 2

(-2,-3) and (-2,0) have the same x. So 0-(-3)=?

Answer 3

3

Answer 4

So there's your radius. Now just put the info into standard form. \[\large (x-h)^{2}~+~(y-k)^{2}=r^{2}\]
\[\large (h,k)~=~Center~coordinates~of~circle\]
\[\large r~=~radius\]

Answer 5

either A or E right?

Answer 6

Do you mean A or D?

Answer 7

right x)

Answer 8

it's D right?

Answer 9

r=3.
\(3^{2}=?\)

Answer 10

9 so A! thanks!

Answer 11

Right, A. And \[\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile \]