what is the value of f(0) for the function...
\[\log_{10} 10+9^{x}+(x-2)(x-1)\]
do you mean ? \[f(x)=\log_{10} (10+9^x+(x-1)(x-2))\]
hmm... no thats not how it asked me but could it have been meant that way?
you answer by replace x with 0 in your expression
\[ \log_{10} 10+9^{0}+(0-2)(0-1) \] let's do the easy part: what is 0-2 ? what is 0-1 ?
\[\log_{10} 10+9^0(-2)(-1)\]
I hope you mean \[ \log_{10} 10+9^{0}+(0-2)(0-1)\\ \log_{10} 10+9^{0}+-2\cdot -1 \]
yes
next, what is -2*-1 ?
2
so we now have \[ \log_{10} 10+9^{0}+ 2 \] next: any number (except 0) raised to the "0 power" is 1. using that rule, what is 9^0 ?
1
so \[ \log_{10} 10+1+2 \\ \log_{10} 10+3 \]
I assume you don't know the log base ten of 10 ? log means "what exponent" base ten to "what exponent" is 10 ? 10^x = 10 what is x ?
you should know 10^0 = 1 10^1 = 10 10^2 = 100
so \[\log_{10} 10\] equals to 1?
yes. If you have a calculator and try log 10 you should get 1 so we now have 1+3
ok got it
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