Question

Find the Value of x and y

Answer 1

\[ Side~opposite~30~degrees~=~Short~Leg~=~SL=x\]\[Side~opposite~60~degrees~=~Long~leg~=~LL=y\]\[Hypotenuse~=~H\] \[\large SL~=~\frac{1}{2}H\] \[\large LL~=~SL\sqrt{3}\]

Answer 2

im kinda confused tho... how would you solve it

Answer 3

if x is the opposite what ratio function would you use?

Answer 4

what do you know about sin and cosine?

Answer 5

To solve the short leg (x), plug in H for the first formula.

Answer 6

We don't really need sin and cosine for this one, since we have a 30-60-90 triangle. Ez mode

Answer 7

dear you are using actually that fact!

Answer 8

In the diagram \[\large H=4\sqrt{2}\] So plug that into \[\large SL~=~\frac{1}{2}H\]

Answer 9

where did you get those ratios you are using otherwise

Answer 10

those numbers you are using came form sin and cos

Answer 11

I'm well aware of that

Answer 12

just wanted to point that since you said no need for sin and cos
so just for the poster to be cleared where those came from

Answer 13

1/2 * 4 (Sqrt)2

Answer 14

Yep. So what would we get from that?

Answer 15

2.82

Answer 16

Yeah, although it may be easier to leave it in the form of \(2\sqrt{2}\) for now.

Answer 17

alright ...

Answer 18

Now that we know that \(SL = 2\sqrt{2}\) we can plug it into the next formula \[\large LL~=~SL\sqrt{3}\]

Answer 19

so it would be 2sqrt2 * Sqrt 3 ???

Answer 20

Yes. \[\large 2\sqrt{2 \times 3}\]

Answer 21

oh i got it now !! thank you very very much LegendarySadist !!!

Answer 22

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