Question

What are the zero(s) of the function f(x) = the quantity of 5 x squared minus 25 x, all over x?

Answer 1

@mathstudent55

Answer 2

@xapproachesinfinity

Answer 3

\[\frac{5x^2 - 25x}{x}\]

what common factor do you see..?

Answer 4

5x

Answer 5

ok... so I'll do that

\[\frac{5x(x - 5)}{x}\]

what common factor do you see in the numerator and denominator..?

Answer 6

x

Answer 7

ok so that leaves

5(x -5) = 0

so what value of x makes the equation true..?

Answer 8

5, 0

Answer 9

only 5 and when x = 0 in the original equation you have a zero denominator, which is undefined

so at x = 0 you have a point of discontinuity...

so the solution is x = 5 which comes from the simplified version of the original equation.

hope it makes sense.

Answer 10

It does! Thank-you:)