Question

Help in Algebra 1 Screenshot Below!!

Answer 1

@Owlcoffee :D :D:D can u help?

Answer 2

On the first part you are asked to use the discriminant to describe the solutions of the quadratic equation.
As you might know, a quadratic equation can be solved using the general formula or "bhaskara's formula":
\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
But this formula has a part we call "discriminant" and as you might have guessed, it is everything inside the radical, the discriminant is often notated with the capital greek letter "delta";
\[\Delta = b^2 - 4ac\]

The discriminant gives away the behavior of the solution of a quadratic equation, therefore, there are 3 possible scenarios:
\[1) \Delta >0\]
If the discriminant is greater than zero, meaning, a positive number, the quadratic equation will have two solutions x1, x2.
\[2) \Delta =0 \]
If the discriminant is equal to zero, then the quadratic equation will have one solution and graphically means that the parabola formed is tangent to the x-axis.
\[3) \Delta <0\]
if the discriminant is negative, the quadratic equation will have no real solutions and graphically means that the parabola formed does not cut the x-axis.

Answer 3

ahhh that makes sense :D so what would B and C be then?

Answer 4

Well, you can use the general formula to solve one, and use factoriation to solve the other.

Answer 5

ok :D Thanks :)