Question

I need help on all of these problems, sometimes using this website: http://phet.colorado.edu/sims/vector-addition/vector-addition_en.html. The questions are attached below. @zepdrix

Answer 1

For the first few questions.

Answer 2

https://www.mathsisfun.com/algebra/vectors.html

Answer 3

https://www.khanacademy.org/math/precalculus/vectors-precalc

Answer 4

http://www.physicsclassroom.com/class/vectors/Lesson-1/Vectors-and-Direction

Answer 5

Maybe, those will help^^

Answer 6

it didn't

Answer 7

attempt at #7

Answer 8

sry, :(

Answer 9

link is broken :(

Answer 10

@zepdrix http://phet.colorado.edu/sims/vector-addition/vector-addition_en.html

Answer 11

so uhhhh which one you up to right now? 0_o

by the way, i would recommend using `style 2`, that one makes the most sense.

Answer 12

@zepdrix I did #1, that's as far as I got. Everything else I attempted but didn't work

Answer 13

Ok let's use trig to explain problem 2, as they have requested.
If the `x component` is `twice the size` of the `y component` we can write that relationship like this: \(\large\rm x=2y\)

Answer 14

does that solve it?

Answer 15

Mmm that's the right idea, yes!
But they want this generalized for ANY vector.
You showed that it works for a specific set of lengths, 11 and 22.

Answer 16

So what we would rather do is call our
\(\large\rm \color{orangered}{x=2y}\) and our \(\large\rm y=y\)

x is twice the length of y, that's how we got that relationship.
So again plug this into your inverse tangent.\[\large\rm \tan^{-1}\left(\frac{y}{\color{orangered}{x}}\right)=\tan^{-1}\left(\frac{y}{\color{orangered}{2y}}\right)\]

Answer 17

Do you see where this is going? :)

Answer 18

yes, I understand what you are implying

Answer 19

11 divided by 22 can be simplified to 1/2.
The same thing will happen with our setup here!
We can cancel the y's and see that the argument simplifies to 1/2.

Again, you'll get 26.6 degrees, but now we've generalized it. yay team

Answer 20

okay, haha, yes I understand, now on to the next one :)

Answer 21

mmmm number 3 should be pretty straight forward.

Answer 22

but what would it look like?

Answer 23

like this?

Answer 24

if i have some vector V
and then I add to that some vector -V,
they'll give me 0, ya?

So draw a vector going off in some direction.
And draw another vector going in the opposite direction.
Illustrated here as an example:

Answer 25

Yah I think yours will work also.
But it'll be easier to setup if both tails start from the origin.

Answer 26

i mean, if both tails are touching.

Answer 27

i dont really understand how to use the `show sum` tool.
trying to figure that out...

Answer 28

oh oh ok i get it now

Answer 29

actually, your example was fine, ya just go with that :)
neeeeext

Answer 30

On your picture that you posted, if you click the "show sum" button,
you should notice that nothing happens.
That's because the sum is zero, so there is nothing to display

Answer 31

so my example works or no?

Answer 32

ya

Answer 33

okay cool. next

Answer 34

4 is the same idea... this should be pretty straight forward.

We just showed that we can add two vectors to get zero.

So now we want to add three vectors and end up with only the first one......
meaning that `the other two vectors added to zero`.

ya? ;o

Answer 35

when I try to press the show sum button it doesnt come up

Answer 36

no, I dont really get 4 either

Answer 37

So for problem 3, we did something like this.
Two vectors added together, gave us nothing, zero.