How many grams of aluminum chloride must decompose to produce 78.3 milliliters of aluminum metal, if the density of aluminum is 2.70 g/mL? Show all steps of your calculation as well as the final answer.

AlCl3 → Al + Cl2

@Photon336 @aaronq @welshfella @dan815

Question

How many grams of aluminum chloride must decompose to produce 78.3 milliliters of aluminum metal, if the density of aluminum is 2.70 g/mL? Show all steps of your calculation as well as the final answer. 

AlCl3 → Al + Cl2

@Photon336 @aaronq @welshfella @dan815

welshfella · Answer

first balance the chemical equation

2 Al Cl3 -->   2 Al + 3 Cl2

welshfella · Answer

next work out the mass of the aluminum  =  78.3 * 2.7 
now from the equation  use the relative atomic masses of the elements to find out how much ALCl3 is needed to form  78.3*2.7 grams of Al.

welshfella · Answer

Al = 26.982
Cl = 35.45

so
from the equation:-

2*26.982 g Al  comes from 2*26.982 + 6*35.45 g of AlCl3

next work out how much AlCl3 comes from 1 g of AL 
then multiply that result by 78.3*2.7