Question

Upon balancing the equation below, how many moles of sulfuric acid are needed to react completely with 8.4 moles of lithium hydroxide? (1 point)

LiOH + H2SO4 yields Li2SO4 + H2O

2.1 moles
4.2 moles
8.4 moles
16.8 moles

Answer 1

@abb0t

Answer 2

Yes?

Answer 3

can you help me on this question please :)

Answer 4

Your first step is to balance do you know how to do that?

Answer 5

no

Answer 6

2 LiOH + H2SO4 = Li2SO4 + 2 H2O

Answer 7

Yep that is balanced

Answer 8

So now we have to determine how may moles of H2SO4 are needed to react with the 8.4mols of LiOH
So the first step to realize is that for every one mole of H2SO4 is used, two moles of LiOH are used. So:
8.4mol LiOH * (1 mol H2SO4/2mol LiOH) * (98.08g/mol H2SO4/1mol H2SO4)= ? g H2SO4

Answer 9

I got 4.2 moles

Answer 10

Ya it would be 4.2 mol of H2SO4

Answer 11

yeas thanks for the help :) :D

Answer 12

No problem!