Question

Amelia rolls two fair number cubes numbered from 1 to 6. She first defines the sample space as shown below:

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

Based on the sample space, what is the probability of getting a total of 4?



6 over 36
5 over 36
4 over 36
3 over 36

Answer 1

@LynFran

Answer 2

@dan815

Answer 3

someone c:

Answer 4

4/36

Answer 5

o wait let me recheck..

Answer 6

ooooo mkay

Answer 7

i dont really understand this part Based on the sample space, what is the probability of getting a total of 4?
getting 4 #??

Answer 8

o i got it...

Answer 9

ok so you need to look at the sample space and add the 2value in the brackets...they must add up to 4...so far i see thiss....
(1,3) 1+3=4
(2,2) 2+2=4
(3,1) 3+1=4
so the probability is 3/36