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differentiate y=cos^-1(tan3x^4)
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Please let me first work through it. It will take one minute.
\(\large\color{black}{ \displaystyle y=\cos^{-1}(\tan~(3x^4)~) }\) at first, \(\large\color{black}{ \displaystyle \cos(y)=\tan~(3x^4)~ }\)
SO basically in derivatives for sin cos and tan, The derivative of sin x is cos x, The derivative of cos x is −sin x (note the negative sign!) and The derivative of tan x is sec2x.
then use Implicit Differentiation
Well solomon seems to have got this lol
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So the answer is cos(y)=tan(3x^4) or is there still more steps.
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