Question

3

Answer 1

This is how i did it.....
Given: 320Hz, N = 14, t = 7sec
Solution:
F = N/t = 14times/7sec = 2Hz
Fb = f1 +- f2
fb = 320Hz + 2 Hz
fb = 322Hz
or
fb = 318Hz

Answer 2

either could be true in this case!!

Answer 3

@Astrophysics

Answer 4

am i right?????????????o_O

Answer 5

This is like the problem we did yesterday, \[\huge f_{beats} = |f_2-f_1|\]
\[\large f_{beats} = \frac{ 14 }{ 7 } = 2 Hz\]\[2Hz = |f_2 - 320 Hz| \implies \pm 2 Hz = f_2-320HZ\] so yes! You're good!

Answer 6

actually that problem is coming right now...right after this question!!! LOL

Answer 7

Again thanks !!! :)

Answer 8

Np ^.^