Question

Need answer verification please (2y)^2+4y
When y=-3
We got 24

Answer 1

when y = -3 we have

\[(2(-3))^2+4(-3)\]
\[(-6)^2 -12 \]
\[36-12 = 24\]

Answer 2

Could you check another?

Answer 3

sure

Answer 4

Thank you, I'm trying to help her finish hers so I can start on mine lol

Answer 5

m^3+3(x+2)
when m=-2 and x=4

Answer 6

I got 10, she got 14

Answer 7

ok so first we need to plug in m=-2 and x = 4
\[m^3+3(x+2) \]
\[(-2)^3+3(4+2)\]
\[\[-8+3(6)\]\]
\[-8+18 = 10 \]

Answer 8

Do you care if I keep typing more?

Answer 9

depends on the topic and difficulty
how many more problems?

Answer 10

Same stuff and I will take whatever help you can give until you dont want to anymore because there is quite a few more

Answer 11

ok...

Answer 12

6k^3+3d
k=-1 and d=-2
We got -12

Answer 13

\[6k^3+3d \] for k=-1 and d = -2
\[6(-1)^3+3(-2) \]
\[6(-1)+3(-2) \rightarrow -6-6 =-12\]

Answer 14

Thanks...
(4+x)^2/x-6 when x=6
We got 100

Answer 15

\[\frac{(4+x)^2}{x-6}\] for x = 6.. wait a minute... this is undefined... if we let x = 6 in the denominator we will have 100/0 and we can't have a 0 in the denominator.

Answer 16

oops it was supposed to be x-1 on the bottom

Answer 17

so 20 is the answer

Answer 18

oH! xxxxxxxxxxxxxxD

Answer 19

\[\frac{(4+x)^2}{x-1}\]
for x = 6
100/5 = 20 yup !

Answer 20

The next one is 4+7/x-2 + 3
when x=5
We got 6 2/3

Answer 21

is it
\[4 + \frac{7}{x}-2 +3\] or
\[4 + \frac{7}{x-2} +3\]
???

Answer 22

I don't understand the format of the question... could you draw it out?

Answer 23

Ill just skip that one I cant figure out how to type it lol

Answer 24

I'll try