A group of adults and students went on a class trip to Washington, DC. The number of male students was 1 more than 7 times the number of adults. The number of female students was half the number of male students. If the total number of people who went on the trip is 82, find the numbers of male students and female students.
I think you just need to setup two equations and solve
@GG1997
are you really sure the work `adult` was not a typo ?
well how do you do that
and I'm positive it's not a typo
idk looks i have problem interpreting the question lol
Lets start by labeling anyways let \(a\) = number of adults \(m\) = number of male students \(f\) = number of female students
`The number of male students was 1 more than 7 times the number of adults.` translates to \[m = 7a+1\tag{1}\]
`The number of female students was half the number of male students` translates to \[f=\frac{m}{2}\tag{2}\]
`the total number of people who went on the trip is 82` translates to \[a+m+f = 82\tag{3}\]
so we have a system with 3 equations, knw how to solve ?
still struggling
lol I really suck at math
basically we have 3 equations and we need to solve 3 unknowns : \(a, m, f\)
ok how
\[m = 7a+1\tag{1}\] \[f=\frac{m}{2}\tag{2}\] \[a+m+f = 82\tag{3}\] rearranging second equation gives, \(m=2f\) plug this in the remaining equations
\[2f = 7a+1\tag{4}\] \[a+2f+f=82\tag{5}\] can you solve this new two equation system with two unknowns ?
do i didvide both sides by 2
You could do that if you want to use substitution
\[2f=7a+1\] dividing 2 both sides gives \[f=\dfrac{7a+1}{2}\] you want to plug this in the other equation and solve \(a\) is it ?
that works, do it
still here ? @GG1997
yes I'm here
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