Question

calculate the rate of heat flow through glass window 3m x 2 m in area and 4.1 mm thick , if the temperature at the inner and outer surface are 18 degree celcius and 13 degree celcius. k for glass is 0.84 J/s.m.C......tq

Answer 1

Here we have to apply the Fourier Law, so the requested rate of heat is given by the subsequent formula:
\[\Large \frac{{\Delta Q}}{{\Delta t}} = kS\frac{{{\theta _2} - {\theta _1}}}{d}\]

Answer 2

where:
\[\Large \begin{gathered}
{\theta _2} - \theta = 18 - 13 = ...^\circ C \hfill \\
\hfill \\
S = 3 \times 2 = ...{m^2} \hfill \\
\hfill \\
d = 4.1 \times {10^{ - 3}}\;meters \hfill \\
\hfill \\
k = 0.84\frac{{joules}}{{\sec \cdot m \cdot ^\circ C}} \hfill \\
\end{gathered} \]

Answer 3

thank you so much!!! @Michele_Laino