Question

I need somebody to walk me through this, I understand the just of it. PLease Help! Medal and Fan!

Answer 1

@dan815

Answer 2

@peachpi

Answer 3

@AllAmericanViking

Answer 4

@Donblue

Answer 5

@ganeshie8

Answer 6

@nincompoop

Answer 7

What is the question? I might be able to help you.

Answer 8

The function H(t) = -16t2 + vt + s shows the height H(t), in feet, of a projectile launched vertically from s feet above the ground after t seconds. The initial speed of the projectile is v feet per second.
Part A: The projectile was launched from a height of 96 feet with an initial velocity of 80 feet per second. Create an equation to find the time taken by the projectile to fall on the ground. (2 points)

Part B: What is the maximum height that the projectile will reach? Show your work. (2 points)

Part C: Another object moves in the air along the path of g(t) = 31 + 32.2t where g(t) is the height, in feet, of the object from the ground at time t seconds.

Use a table to find the approximate solution to the equation H(t) = g(t), and explain what the solution represents in the context of the problem? [Use the function H(t) obtained in Part A, and estimate using integer values] (4 points)

Part D: Do H(t) and g(t) intersect when the projectile is going up or down, and how do you know? (2 points)

Answer 9

Is this FLVS?

Answer 10

Yep!

Answer 11

Algebra?

Answer 12

Algebra 1 semester 2, just this and im done the whole thing

Answer 13

did you plug in the numbers to create the equation for A?

Answer 14

i tried to but didnt quite understand

Answer 15

Ok I just finished it yesterday. Maybe I can see if I had it too

Answer 16

this is what i got
H(t) = -16(96)^2 + 80(96) + 96

Answer 17

\(H(t)=-16t^2+vt+s\) is the basic equation. You need to replace the v with the velocity they gave you, and replace the s with the initial height. t is the variable, so it stays the same.

Answer 18

all you need to do is change v to 80 and s to 96

Answer 19

so the velocity is 80 fps
and the height is 96
but whats the time?

Answer 20

?

Answer 21

what about t?

Answer 22

time is the independent variable. the projectile has a different height for different values of time. It's 96 in the beginning and then goes up and comes back down

Answer 23

i actually do need time to type, you know?

Answer 24

sorry, okay s it would be H(t) = -16t^2 + 80t + 96?

Answer 25

yes

Answer 26

Sweet! now could you help with b?

Answer 27

would you solve for t?

Answer 28

Yes, for B, the height's going to be the y-coordinate of the vertex using the equation from a.

Answer 29

\[t=-\frac{ b }{ 2a }\]
Look familiar?

Answer 30

then once you have that t, plug it in to get the height

Answer 31

Yes, okay soi got 5/2?

Answer 32

that's the right time. now put it in for t in the equation from A

Answer 33

\[-16(5/2)^2+80(5/2)+96\]

Answer 34

oh okay, and then solve?

Answer 35

yes

Answer 36

i got 196?

Answer 37

yes that's right

Answer 38

C?

Answer 39

for c, create a table for the values 0 through 5 and plug them into both equations

Answer 40

You're looking for the t where you get the same (or pretty close) H for both equations

Answer 41

okay let me see

Answer 42

is it possible to solve algebraicly without a table?

Answer 43

yes, but you probably haven't done it in algebra I.