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You have 7 balls that are each a different color of the rainbow. In how many distinct ways can these balls be ordered?
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1 7 49 343 5,040
Start easy. If you had one ball, how many ways can you order it?
looks like @ybarrap has this one!
whats the answer ?
each of the seven balls is distinct; there are \(7!\) such ways of arranging them since there are \(7\) possibilities for the first ball of the order, the other \(6\) for the second, the remaining \(5\) for the third, then \(4\), \(3\), \(2\), and ultimately \(1\) for the final position -- so \(7\times6\times5\times4\times3\times2\times1=7!=5040\)
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