Question

Cosx/(1+sinx)+(1+sinx)/cos(x)=2sec(x)

I don't know how this is done at all and its so frustrating -__-

Answer 1

\(\dfrac{\cos x}{1 + \sin x} + \dfrac{1 + \sin x}{\cos x} = 2 \sec x\)

\(\dfrac{\cos x}{1 + \sin x} \times \dfrac{\cos x}{\cos x} + \dfrac{1 + \sin x}{\cos x} \times \dfrac{1 + \sin x}{1 + \sin x}= 2 \sec x\)

\(\dfrac{\cos^2 x}{(1 + \sin x) \cos x} + \dfrac{(1 + \sin x)^2}{(1 + \sin x) \cos x } = 2 \sec x\)

\(\dfrac{\color{red}{\cos^2 x} + 1 + 2 \sin x + \color{red}{\sin^2 x}} {(1 + \sin x) \cos x } = 2 \sec x\)

\(\dfrac{1+ 2 \sin x + \color{red}{1}} {(1 + \sin x) \cos x } = 2 \sec x\)

\(\dfrac{2 + 2 \sin x}{1 + \sin x)\cos x} = 2 \sec x\)

\(\dfrac{2\cancel{(1 + \sin x)}}{\cancel{(1 + \sin x)}\cos x} = 2 \sec x\)

\(\dfrac{2}{\cos x} = 2 \sec x\)

\(2 \sec x = 2 \sec x\)

Answer 2

Start simply by finding the LCD of the two fractions on the left sides and adding the fractions together.
Then simplify using the identity \(\sin ^2 x + \cos ^2 x = 1\) shown in red above.

Answer 3

@mathstudent55 you are soo amazing! You seriously made it look so easy lol I appreciate you taking the time to figure it out!!

Answer 4

You are very welcome.
I was glad to be of help.