Question

If f(x) = 1 – x, which value is equivalent to |f(i)|? options are:
A.0
B.1
C. √2
D. √-1

Answer 1

\[|a+bi|=\sqrt{a^2+b^2}\]

Answer 2

B should be the closest

Answer 3

it actually isn't B

Answer 4

Bcuz i = sqrt -1, and the absolut value of a negative number is a positive number

Answer 5

\[f(i)=1-i \\ |f(i)|=|1-i|=?\]

Answer 6

sorry guys but im still in the blue here ahahah

Answer 7

Oh so its A!!!

Answer 8

\[|1-i|=\sqrt{1^2+1^2}=?\]

Answer 9

Cuz 1 - 1 = 0!

Answer 10

Bam!! Medal me please

Answer 11

or if you wanted to look at it as
\[\sqrt{1^2+(-1)^2} \text{ instead of } \sqrt{1^2+1^2}\]

Answer 12

ayyyy lmao

Answer 13

all I'm asking you to do is do the 1+1 underneath the radical

Answer 14

\[|a+bi|=\sqrt{a^2+b^2} \ \\ \text{ and you have } \\ |1+-1i|=\sqrt{1^2+(-1)^2}=\sqrt{1^2+1^2}=?\]
can you finish this ?

Answer 15

OOOOOOOO THANKS MAN LMAO I DONT KNOW HOW I DIDNT SEE THAT ahha its √2

Answer 16

yep :)

Answer 17

Dang I didn't even see that answer choice. I'm Dyslexic, I thought it said \[\sqrt{21}\]