Question

Simplify the expression where possible.
\[(-4x ^{2})^{2}\]

Answer 1

Hint: \(\sf\Large (a^b)^c = a^{b \times c}\)

Answer 2

ditto

Answer 3

\[-4^{4}\]?

Answer 4

\[[-4^1*x^2]^2\]

Answer 5

What? I'm confused.

Answer 6

\[= (-4^1)^2*(x^2)^2\]

Answer 7

Another hint: \(\sf\Large (xy)^z = x^{z} y^{z}\)

Answer 8

@AbdullahM wrote the correct general power rules to remember... good luck

Answer 9

(:

Answer 10

\[-4x ^{4}?\]

Answer 11

\(\bf (-4x ^{2})^{2}\implies (-4^1x^{2})^2\implies (-4^1)^2(x^2)^2\implies -4^{1\cdot 2}x^{2\cdot 2}\implies -4^2x^4\)

Answer 12

@Falling_In_Katt when you square the -4, it turns into (-4)^2 = (-4)*(-4) = +16

notice how it's positive and not negative

Answer 13

Ohhh Thank you!

Answer 14

It's positive because two negatives multiply to a positive

Answer 15

hmmm actually shold be positive yes

Answer 16

\(\bf (-4x ^{2})^{2}\implies (-4^1x^{2})^2\implies (-4^1)^2(x^2)^2
\\ \quad \\
(-4)(-4)(x)^4\implies +16x^4\)