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x^(sqrt(log(x)))=10^8
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\[x^{\sqrt{\log(x)}}=10^{8}\]
I would start by taking log( ) of both sides
\[x ^{\sqrt{\log(x)}}=10^8\] \[\log \left( x ^{\sqrt{logx}} \right)=\log \left( 10^8 \right)\] \[\sqrt{logx}logx=8\log10\] \[\left( logx \right)^{\frac{ 3 }{ 2 }}=8*1=8\] \[\log x=8^{\frac{ 2 }{ 3 }}=\left( 2^3 \right)^\frac{ 2 }{ 3 }=2^2=4,x=10^4\]
perfect!
thanks guys
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