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Mathematics 7 Online
OpenStudy (anonymous):

Simplify the trigonometric expression

OpenStudy (decentnabeel):

@EllenJaz17 what is the expression

OpenStudy (anonymous):

\[\frac{ \sin ^{2} }{ 1-}\]

OpenStudy (anonymous):

its supposed to be sin^2theta/1-cos theta

OpenStudy (decentnabeel):

the answer is 1

OpenStudy (decentnabeel):

correct @EllenJaz17

OpenStudy (anonymous):

\[\frac{ \sin ^{2}\theta }{1-cos }\]

OpenStudy (anonymous):

and theta is after the cos.

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (decentnabeel):

\[\mathrm{Use\:the\:following\:identity}:\quad \:1=\cos ^2\left(x\right)+\sin ^2\left(x\right)\] \[=\frac{\sin ^2\left(θ\right)}{\cos ^2\left(θ\right)-\cos ^2\left(θ\right)+\sin ^2\left(θ\right)}\] \[\frac{\sin ^2\left(θ\right)}{-\cos ^2\left(θ\right)+\cos ^2\left(θ\right)+\sin ^2\left(θ\right)}\] \[\mathrm{Add\:similar\:elements:}\:-\cos ^2\left(θ\right)+\cos ^2\left(θ\right)=0\] \[=\frac{\sin ^2\left(θ\right)}{\sin ^2\left(θ\right)+0}\] \[=\frac{\sin ^2\left(θ\right)}{\sin ^2\left(θ\right)}\] =1

OpenStudy (decentnabeel):

this is the 1 problem

OpenStudy (anonymous):

OpenStudy (anonymous):

Those are my answer options

OpenStudy (decentnabeel):

ohhhhhh you needed just answer @EllenJaz17

OpenStudy (anonymous):

yeah. Those are my options A-D in the attachments

OpenStudy (anonymous):

Would the answer be C?

OpenStudy (anonymous):

@DecentNabeel

OpenStudy (misty1212):

HI!!

OpenStudy (anonymous):

hey

OpenStudy (misty1212):

is it just \[\huge \frac{1-\sin(x)}{\cos(x)}\]

OpenStudy (anonymous):

So it's b?

OpenStudy (misty1212):

no i am still trying to figure out what the original question one

OpenStudy (misty1212):

was

OpenStudy (anonymous):

Simplify it

OpenStudy (misty1212):

can you repost the original one

OpenStudy (decentnabeel):

\[\mathrm{Simplify}\:\frac{1-\sin \left(θ\right)}{\cos \left(θ\right)}:\quad \left(1-\sin \left(θ\right)\right)\sec \left(θ\right)\]

OpenStudy (misty1212):

\[\huge \frac{\sin^2(\theta)}{1-\cos(\theta)}\]

OpenStudy (misty1212):

we can do a couple things if that is the original question

OpenStudy (anonymous):

Simplify the trigonometric expression (is the question)

OpenStudy (misty1212):

perhaps the easiest it to rewrite \(\sin^2(\theta)\) as \(1-\cos^2(\theta)\) then factor

OpenStudy (anonymous):

Use the identity sin^2 = 1-cos^2. Then factor it into (1+cos)(1-cos). Then cancel

OpenStudy (misty1212):

\[\frac{\sin^2(\theta)}{1-\cos(\theta)}=\frac{1-\cos^2(\theta)}{1-\cos(\theta)}=\frac{(1+\cos(\theta))(1-\cos(\theta))}{1-\cos(\theta)}=1+\cos(\theta)\]

OpenStudy (anonymous):

Is that the final answer?

OpenStudy (misty1212):

not sure if that is an answer choice, but if it is, pick that one

OpenStudy (anonymous):

It is! Thank you!

OpenStudy (misty1212):

\[\color\magenta\heartsuit\]

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