Question

I^15 =

Answer 1

i^2 = -1 , i^3 = ii and i^4 = 1

Answer 2

* i^3 = -i

Answer 3

i^12 = (i^4)^3 = 1

i^15 = i^4 * i^3

Answer 4

* last line is
i^15 = i^12 * i^3

Answer 5

I'm so confused.

Answer 6

i^2 = -1

thats by definition right?

Answer 7

wait...would it be -i

Answer 8

1 raised to any power is always going to be 1. You could right it out as 1*1*1*1*1*1*1*1*1*1*1*1*1*1*1=1 if you wanted, but it will always be 1.

Answer 9

yes -i is correct

Answer 10

Oh thank you!

Answer 11

we have:
\[{i^2} = - 1 \Rightarrow {i^{14}} = {\left( {{i^2}} \right)^7} = {\left( { - 1} \right)^7} = - 1 \Rightarrow {i^{15}} = {i^{14}}i = ...?\]

Answer 12

i assumed this was an i - in the question - but it looks like 1 lol!