Question

The curve \(y = \sqrt{x}\), from \(x = 0\) to \(x = 9\) is rotated about the x-axis to form a solid, which is then rotated about the y-axis to form a larger solid. What is the volume of the larger solid? I know the answer is 1944π/5, but can someone help me get to this answer?

Answer 1

Actually, I think I may have gotten it. Can someone confirm if this logic is correct? Doing this double rotation is equivalent to rotating \(y = 2\sqrt{x}\) around the y-axis.

Answer 2

Yeah that sounds right to me.

Answer 3

Thanks. Just had a moment of stupidity there.