Question

A ball is thrown straight up with an initial velocity of 20.0 ft/s. How long does it take to reach its maximum height?

This is my work:

a = Vf - Vi / t (-9.80 m/s^2) (3.28 ft / 1 m) = - 32.1 ft / s^2
t = (Vf - Vi) / a
t = (0 - 20.0 ft/s) / (-32.1 ft/s^2)
t = 0.62305 s
t = 0.623 s ← is that right?

Answer 1

your answer is correct!