if 0 is less than or equal to t which is less than 2pi solve cos t + 1=2sin^2t
any idea?

Question

if 0 is less than or equal to t which is less than 2pi solve cos t + 1=2sin^2t
any idea?

anonymous · Answer

Do you have options?

anonymous · Answer

No all on our own

anonymous · Answer

cos(t) + 1  = 2 sin^2 t 

substitute , sin^2 t = 1 - cos^2 t
from the identity  sin^2 t + cos^2 t = 1 

cos(t) + 1  = 2 ( 1 - cos^2 t ) 
distribute
cos (t) + 1 = 2 - 2 cos^2 t 
2 cos^2 (t) + cos (t) + 1 - 2  = 0
2 cos^2 (t) + cos (t) -1  = 0
factor
(2 cos t - 1 ) ( cos t + 1 )  = 0

anonymous · Answer

@SurpriseBreeze i think you forgot to divide by two tho cuz look at number for equation

anonymous · Answer

four**

anonymous · Answer

I just googled it... sorry .-. I like your elephant! :D

anonymous · Answer

@SurpriseBreeze So is your answer right tho? and haha thanks