Find an exact value. cos(pi/12)
i think we can use cos 2x = 2cos^2x - 1 cos (pi/6) = 2 cos^ (pi/12) - 1 cos pi/6 = sqrt3/2
they want you to use the half angle formula \[\cos \frac{ x }{ 2 }= \pm \sqrt{\frac{ 1+cosx }{ 2 }}\]
oh ok well just plug cos x ( in this case cos pi/6) into the firmula and work it out
when I do I don't get the right answer
The answer options are (sqrt6+sqrt2)/4 (-sqrt6+sqrt2)/4 (sqrt6-sqrt2)/4 (-sqrt6-sqrt2)/4
yes its an awkward one to work out
How would you work it out?
= sqrt [( 1 + sqrt3/2)/ 2]
How do you get from that to one of the answers? I dont understand how you get a sqrt 6 out of any of that
i simplified that to (1/2)( sqrt(2 + sqrt3))
i agree I think those answers are wrong.
because if you go on the calculator cos pi/12 = 0.9659 and my answers comes to the same value
oh hold on (sqrt6+sqrt2)/4 comes to 0.9659 as well so that one is right
- also the negative of that is another solution
I'm not sure how they got to that ...
Join our real-time social learning platform and learn together with your friends!