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Help please! d=vt+(1/2)at squared Solve for v.
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\[d=vt+(1/2)at ^{2}\]
\[d=vt+\frac{1}{2}at^2\] you want \(v\) right?
Yes
subtract \(\frac{1}{2}at^2\) from both sides, then divide both sides by \(t\)
"subtract" really just means "write it"
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\[d=vt+\frac{1}{2}at^2\\ d-\frac{1}{2}at^2=vt\] is the first step
then put it over \(t\) and you are done
Thank you!
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