Let u = <-5, -3>, v = <-6, -1>. Find -3u + 5v.
@hero @dan815 @nincompoop @mathstudent55 @wio @radar @undeadknight26
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OpenStudy (misty1212):
HI!!
OpenStudy (misty1212):
multiply both entries in \(u\) by \(-3\)
multiply both entries in \(v\) by \(5\)
then add
OpenStudy (anonymous):
huh? @misty1212
OpenStudy (misty1212):
i don't really know another way to say it
OpenStudy (misty1212):
u has two numbers right?
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OpenStudy (anonymous):
can u show me? @misty1212
OpenStudy (misty1212):
multiply each of them by \(-3\)
OpenStudy (misty1212):
\[u=<-5,-3>\\
-3u=-3<-5,-3>=<15,9>\]
OpenStudy (misty1212):
in other words, multiply each entry by \(-3\)
OpenStudy (misty1212):
repeat to find \[5v=5<-6,-1>\]
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OpenStudy (anonymous):
so its <-30,-5> @misty1212
OpenStudy (misty1212):
yes
OpenStudy (misty1212):
then add
OpenStudy (anonymous):
can u help me with another? @misty1212
OpenStudy (misty1212):
did you add them yet?
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OpenStudy (anonymous):
yes i got <-15,4> @misty1212
OpenStudy (misty1212):
oops yes you are right sorry
OpenStudy (anonymous):
can u help me with another? @misty1212
OpenStudy (misty1212):
ok sure
OpenStudy (anonymous):
Find a • b.
a = 4i + 3j, b = -4i + 4j
-4
28
<-16, 12>
<0, 7>
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OpenStudy (misty1212):
is that a dot between them?
OpenStudy (anonymous):
i think it times
OpenStudy (misty1212):
i think it means the "dot product"
OpenStudy (misty1212):
\[<4,3>\cdot<-4,4>=4\times (-4)+3\times 4\]
OpenStudy (misty1212):
it is a number, not a vector
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OpenStudy (misty1212):
\[-16+12=-4\] in other words
OpenStudy (anonymous):
Find the first six terms of the sequence.
a1 = -7, an = 2 • an-1
-7, -14, -12, -10, -8, -6
0, 2, -14, -12, -10, -8
-7, -14, -28, -56, -112, -224
-14, -28, -56, -112, -224, -448
OpenStudy (anonymous):
@misty1212
OpenStudy (misty1212):
start with \(-7\)
OpenStudy (misty1212):
then multiply it by 2 to get the next number
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OpenStudy (misty1212):
\[-7,-7\times 2,-7\times 2\times 2...\]
OpenStudy (misty1212):
so this one
\[ -7, -14, -28, -56, -112, -224\]
OpenStudy (anonymous):
Find the standard form of the equation of the parabola with a focus at (0, 4) and a directrix at y = -4.
y = 1 divided by 16x2
y2 = 16x
y2 = 4x
y = 1 divided by 4x2
@misty1212
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OpenStudy (misty1212):
yup looks good
OpenStudy (anonymous):
Find an explicit rule for the nth term of the sequence.
3, -12, 48, -192, ...
an = 3 • 4n - 1
an = 3 • 4n + 1
an = 3 • (-4)n - 1
an = 3 • (-4)n
@misty1212
OpenStudy (misty1212):
see how the signs change?
OpenStudy (anonymous):
yes by -4 @misty1212
OpenStudy (misty1212):
so only \[a_n=3(-4)^{n-1}\] makes any sense
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OpenStudy (anonymous):
one last one? @misty1212
OpenStudy (misty1212):
kk
OpenStudy (anonymous):
Use graphs and tables to find the limit and identify any vertical asymptotes of the function.
OpenStudy (misty1212):
? vertical asymptote is where the denominator is zero, so \(x=5\)
OpenStudy (anonymous):
what is the limit @misty1212
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