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Mathematics 15 Online
OpenStudy (anonymous):

MM plain candies come in various colors. According to the MM/Mars Department of Consumer Affairs, the distribution of colors for plain MM candies is: Colors-Purple,Yellow,Red,Orange,Green,Blue,Brown Percentage-20%,20%,20%,10%,10%,10%,10%. Suppose you have a large bag of plain MM candies and you take one candy at random. Find the P(purple candy or orange candy) a. 10% b. 20% c. 30% d. 40%

OpenStudy (anonymous):

There are some questions that accompany this one.

OpenStudy (anonymous):

Using the information from the question, are the outcomes mutually exclusive? Why or why not? a. yes, they have the same probability b. no, they have the same probability c. yes, you are only drawing one MM so orange or purple cannot occur at the same time. d. no, you are only drawing one MM so orange or purple cannot occur at the same time.

OpenStudy (anonymous):

Using the information from the problem, what is P(not blue candy)? a. 20% b. 10% c. 90% d. 80%

jimthompson5910 (jim_thompson5910):

the two events "purple" and "orange" are mutually exclusive, so we can use this formula P(purple candy or orange candy) = P(purple) + P(orange) P(purple candy or orange candy) = P(purple) + P(orange) P(purple candy or orange candy) = (20%) + (10%) P(purple candy or orange candy) = 30%

jimthompson5910 (jim_thompson5910):

they are mutually exclusive because you can only pick one color at a time. In that case, you can only pick purple or orange. But not both at the same time.

OpenStudy (anonymous):

Yeah, that makes sense.

jimthompson5910 (jim_thompson5910):

what is P(not blue) equal to?

OpenStudy (anonymous):

10%?

jimthompson5910 (jim_thompson5910):

that's P(blue)

jimthompson5910 (jim_thompson5910):

what's the probability of not getting blue

OpenStudy (anonymous):

oh, sorry :p 90%

jimthompson5910 (jim_thompson5910):

correct

OpenStudy (anonymous):

Thanks

jimthompson5910 (jim_thompson5910):

np

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