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Mathematics 9 Online
OpenStudy (anonymous):

Find the indicated limit, if it exists.

OpenStudy (anonymous):

limx→9f(x),f(x)=[x+927−xx<9x≥9]

OpenStudy (anonymous):

hartnn (hartnn):

have you tried a similar question before ?

OpenStudy (anonymous):

No.

OpenStudy (anonymous):

I'm not familiar with matrices in this type of problem

hartnn (hartnn):

Know about left hand and right hand limits?

OpenStudy (anonymous):

Yeah, I guess

hartnn (hartnn):

so could you find those limits for f(x) ?

OpenStudy (anonymous):

I don't really know how to do this with matrices.

OpenStudy (anonymous):

IS the limit 18?

hartnn (hartnn):

its not a matrix :) its a piecewise function, when x<9, f(x) = x+9 when x>= 9, f(x) = 27-x

hartnn (hartnn):

how did you find out that the limit = 18 ?

OpenStudy (anonymous):

As x approaches nine, f(x) approaches 18. 9+9=18

OpenStudy (anonymous):

Does that make sense, or am I completely wrong?

hartnn (hartnn):

that makes one-third sense :) let me explain,

OpenStudy (anonymous):

Gladly.

hartnn (hartnn):

so, we need to find whether x approaches same number when x<9, x=9, x>9 if for all these 3 conditions, f(x) approaches same number, then you limit exist! and the limit value = that number.

hartnn (hartnn):

for x>9, we use x>=9 function which is 27-x so, 27- 9 =18 for x = 9, we use x>=9 again, which is 27-x = 18

OpenStudy (anonymous):

So the limit does exist?

OpenStudy (anonymous):

and it is 18

hartnn (hartnn):

for x<9, we use x+9 function so 9+9 = 18 so we indeed get 18 for all 3 conditions! hence limit exist and is = 18 :)

OpenStudy (anonymous):

Thank you.

hartnn (hartnn):

hope you can try next problem on your own now :) and welcome ^_^

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