Question

5(cos^2)60 + 4(sec^2)45 - (tan^2)45 = x
Find x
@Michele_Laina

Answer 1

is 40 degrees the angle of the second term?

Answer 2

45*

Answer 3

ok!

Answer 4

?
How to solve?
?

Answer 5

we have to keep in mind these values:
\[\Large \begin{gathered}
\cos 60 = \frac{1}{2} \Rightarrow {\left( {\cos 60} \right)^2} = \frac{1}{4} \hfill \\
\hfill \\
\sec 45 = \frac{1}{{\cos 45}} = \frac{1}{{\sqrt 2 /2}} = \frac{2}{{\sqrt 2 }} = \sqrt 2 \hfill \\
{\left( {\sec 45} \right)^2} = 2 \hfill \\
\hfill \\
\tan 45 = 1 \Rightarrow {\left( {\tan 45} \right)^2} = 1 \hfill \\
\end{gathered} \]

Answer 6

Ok!

Answer 7

please substitute them into your equation

Answer 8

OMG!!!
ISY SEC 30 NETHER 40 NOR 45 :(

Answer 9

ok! I will rewrite the right value

Answer 10

OK!

Answer 11

here are the right values:

\[\Large \begin{gathered}
\cos 60 = \frac{1}{2} \Rightarrow {\left( {\cos 60} \right)^2} = \frac{1}{4} \hfill \\
\hfill \\
\sec 30 = \frac{1}{{\cos 30}} = \frac{1}{{\sqrt 3 /2}} = \frac{2}{{\sqrt 3 }} \hfill \\
{\left( {\sec 30} \right)^2} = \frac{4}{3} \hfill \\
\hfill \\
\tan 45 = 1 \Rightarrow {\left( {\tan 45} \right)^2} = 1 \hfill \\
\end{gathered} \]

Answer 12

so, after a simple substitution, we get:
\[\Large \left( {5 \times \frac{1}{4}} \right) + \left( {4 \times \frac{4}{3}} \right) - 1 = x\]

Answer 13

please simplify