Question

Fan and Medal!!!
What is the third term of a sequence that has a first term of 3 and a common ratio of 3?

1/3
9
27

Answer 1

third term = a1 r^2

where a1 = first term , r = common ratio

Answer 2

3*3^2
=9*3=27

Answer 3

@welshfella is that right?

Answer 4

hint
by definition of geometric sequence, we have:
\[\Large \begin{gathered}
{a_1} = 3 \hfill \\
{a_2} = 3{a_1} = ... \hfill \\
{a_3} = 3{a_2} = ... \hfill \\
\end{gathered} \]

Answer 5

yes


the nth term = a1 r^(n-1)

here a1 = 3 and r = 3