Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

can someone help me please?:)

OpenStudy (anonymous):

OpenStudy (xapproachesinfinity):

1 step is okay yes we can square root both sides no problem right?

OpenStudy (anonymous):

sure

OpenStudy (xapproachesinfinity):

oh that's second step not first

OpenStudy (xapproachesinfinity):

first is just equation itself

OpenStudy (anonymous):

yea

OpenStudy (xapproachesinfinity):

so 1 and 2 no problem

OpenStudy (hba):

Do you think there is a fault in the 3rd step?

OpenStudy (xapproachesinfinity):

3 now what do you think

OpenStudy (xapproachesinfinity):

look at one side of the equation at a time

OpenStudy (anonymous):

sorry, my laptop is lagging,and it step 3 looks fine to me:S

OpenStudy (xapproachesinfinity):

hehe can we do this \(\sqrt{a^2+b^2}=a+b?\)

OpenStudy (anonymous):

i guess not lol

OpenStudy (hba):

Well as @xapproachesinfinity said the R.H.S is fine as \[\sqrt{c^2} = c \] as they cancel

OpenStudy (xapproachesinfinity):

yes it is not allowed

OpenStudy (anonymous):

rhs?

OpenStudy (hba):

But it should be something like \[\sqrt{(a+b)^2}\] to become a+b

OpenStudy (xapproachesinfinity):

right hand side :)

OpenStudy (hba):

So to get that we know that we want something like \[\sqrt{a^2+2ab+b^2}\]

OpenStudy (xapproachesinfinity):

for this \(\sqrt{b^2+a^2}\) we cannot do anything to it

OpenStudy (hba):

We cannot? :o

OpenStudy (xapproachesinfinity):

yes we can't as far as the problem is concerned!

OpenStudy (hba):

We can solve it by adding root(2ab) on both sides?

OpenStudy (anonymous):

im confused lol

OpenStudy (xapproachesinfinity):

hmm you meant \(|c|+\sqrt{2ab}=\sqrt{a^2+b^2}+\sqrt{2ab }\)

OpenStudy (xapproachesinfinity):

is that what you saying ?

OpenStudy (hba):

No that won't do but we can add something to it so it becomes root(a^2+b^2+2ab)

OpenStudy (xapproachesinfinity):

you can't you add 2ab under the root so you must subtract it under the root

OpenStudy (hba):

Well we shouldn't had done this step in the first place lol :p

OpenStudy (xapproachesinfinity):

this problem we need to go back to a^2+b^2=c^2 solve a a^2=c^2-b^2 take root root(a^2)=root(c^2-b^2) |a|=root(c^2-b^2) a=+-root(c^2-b^2) the correct approach

OpenStudy (hba):

We could have done something like a^2 = c^2 - b^2 so we'd get a= root(c^2-b^2) for an answer

OpenStudy (hba):

Lol we just wrote the samething

OpenStudy (xapproachesinfinity):

yeah true

OpenStudy (xapproachesinfinity):

but we need +- too

OpenStudy (anonymous):

:S

OpenStudy (hba):

Agreed

OpenStudy (hba):

But the ques says +

OpenStudy (xapproachesinfinity):

eh i didn;t read that positive reals part lol

OpenStudy (xapproachesinfinity):

so it has to be a=root(c^2-b^2)

OpenStudy (anonymous):

yall are arguing a question which you both know but are not helping the actual person who needs help, both of u just completly confused me

OpenStudy (hba):

@Sammii09 LoL

OpenStudy (xapproachesinfinity):

ok now we need to promptly do this problem first step checked second step no we need to solve for a^2 third step square rroot both sides 4th step a=... that is it

OpenStudy (hba):

I'm just gonna leave @xapproachesinfinity is here

OpenStudy (xapproachesinfinity):

haha lol @Sammii09

OpenStudy (xapproachesinfinity):

look at my comment before this i did the problem

OpenStudy (anonymous):

ok

OpenStudy (xapproachesinfinity):

first step is okay 2 step no ( we need to isolate a^2 in one side) 3 step (no that's not allowed) (suggest take square root of both side of this equation a^2=c^2-b^2) 4 step no (since third is wrong 4 will also be wrong) (suggested a=root(c^2-b^2)) done!

OpenStudy (anonymous):

okay thanks

OpenStudy (xapproachesinfinity):

no problem

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!