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OpenStudy (anonymous):
OpenStudy (xapproachesinfinity):
1 step is okay yes
we can square root both sides no problem right?
OpenStudy (anonymous):
sure
OpenStudy (xapproachesinfinity):
oh that's second step not first
OpenStudy (xapproachesinfinity):
first is just equation itself
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OpenStudy (anonymous):
yea
OpenStudy (xapproachesinfinity):
so 1 and 2 no problem
OpenStudy (hba):
Do you think there is a fault in the 3rd step?
OpenStudy (xapproachesinfinity):
3 now what do you think
OpenStudy (xapproachesinfinity):
look at one side of the equation at a time
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OpenStudy (anonymous):
sorry, my laptop is lagging,and it step 3 looks fine to me:S
OpenStudy (xapproachesinfinity):
hehe can we do this \(\sqrt{a^2+b^2}=a+b?\)
OpenStudy (anonymous):
i guess not lol
OpenStudy (hba):
Well as @xapproachesinfinity said the R.H.S is fine as \[\sqrt{c^2} = c \] as they cancel
OpenStudy (xapproachesinfinity):
yes it is not allowed
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OpenStudy (anonymous):
rhs?
OpenStudy (hba):
But it should be something like \[\sqrt{(a+b)^2}\] to become a+b
OpenStudy (xapproachesinfinity):
right hand side :)
OpenStudy (hba):
So to get that we know that we want something like \[\sqrt{a^2+2ab+b^2}\]
OpenStudy (xapproachesinfinity):
for this \(\sqrt{b^2+a^2}\) we cannot do anything to it
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OpenStudy (hba):
We cannot? :o
OpenStudy (xapproachesinfinity):
yes we can't as far as the problem is concerned!
OpenStudy (hba):
We can solve it by adding root(2ab) on both sides?
OpenStudy (anonymous):
im confused lol
OpenStudy (xapproachesinfinity):
hmm you meant \(|c|+\sqrt{2ab}=\sqrt{a^2+b^2}+\sqrt{2ab }\)
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OpenStudy (xapproachesinfinity):
is that what you saying ?
OpenStudy (hba):
No that won't do but we can add something to it so it becomes root(a^2+b^2+2ab)
OpenStudy (xapproachesinfinity):
you can't you add 2ab under the root so you must subtract it under the root
OpenStudy (hba):
Well we shouldn't had done this step in the first place lol :p
OpenStudy (xapproachesinfinity):
this problem we need to go back to a^2+b^2=c^2
solve a
a^2=c^2-b^2
take root
root(a^2)=root(c^2-b^2)
|a|=root(c^2-b^2)
a=+-root(c^2-b^2) the correct approach
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OpenStudy (hba):
We could have done something like
a^2 = c^2 - b^2
so we'd get
a= root(c^2-b^2) for an answer
OpenStudy (hba):
Lol we just wrote the samething
OpenStudy (xapproachesinfinity):
yeah true
OpenStudy (xapproachesinfinity):
but we need +- too
OpenStudy (anonymous):
:S
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OpenStudy (hba):
Agreed
OpenStudy (hba):
But the ques says +
OpenStudy (xapproachesinfinity):
eh i didn;t read that positive reals part lol
OpenStudy (xapproachesinfinity):
so it has to be a=root(c^2-b^2)
OpenStudy (anonymous):
yall are arguing a question which you both know but are not helping the actual person who needs help, both of u just completly confused me
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OpenStudy (hba):
@Sammii09 LoL
OpenStudy (xapproachesinfinity):
ok now we need to promptly do this problem
first step checked
second step no we need to solve for a^2
third step square rroot both sides
4th step a=... that is it
OpenStudy (hba):
I'm just gonna leave @xapproachesinfinity is here
OpenStudy (xapproachesinfinity):
haha lol @Sammii09
OpenStudy (xapproachesinfinity):
look at my comment before this
i did the problem
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OpenStudy (anonymous):
ok
OpenStudy (xapproachesinfinity):
first step is okay
2 step no ( we need to isolate a^2 in one side)
3 step (no that's not allowed) (suggest take square root of both side of this equation
a^2=c^2-b^2)
4 step no (since third is wrong 4 will also be wrong) (suggested a=root(c^2-b^2))
done!