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Mathematics 14 Online
OpenStudy (anonymous):

MEDAL***Please help use spherical coordinates to find the volume cut out from the sphere x^2+y^2+z^2=1 by the planes z=1/2 and z=0

OpenStudy (anonymous):

@ganeshie8

ganeshie8 (ganeshie8):

Try \(\rho : ~0\to 1 \) \(\theta : ~0\to 2\pi \) \(\phi : ~\frac{\pi}{3}\to \frac{\pi}{2}\)

OpenStudy (anonymous):

as my limits for triple integration?

ganeshie8 (ganeshie8):

Yes

OpenStudy (anonymous):

p is dx θ is dy ϕ is dz?

OpenStudy (anonymous):

whats the functions im integrating?

ganeshie8 (ganeshie8):

Hmm @Loser66 I didn't get your question..

ganeshie8 (ganeshie8):

@jyar what do you know about spherical coordinates ?

OpenStudy (anonymous):

there related to the cartesian coordinates and its in 3d points (r, θ , ϕ )

ganeshie8 (ganeshie8):

what do \(\rho, \theta\) and \(\phi\) represent ?

OpenStudy (anonymous):

angles projected from the xyz plane

OpenStudy (loser66):

.

OpenStudy (anonymous):

p^2=x^2+y^2+z^2

ganeshie8 (ganeshie8):

|dw:1436648757792:dw|

ganeshie8 (ganeshie8):

For any point \((\rho, \theta, \phi)\) in space, \(\rho\) is the "distance" from origin \(\theta\) is the angle in xy plane with the positive x axis \(\phi\) is the angle with positive z axis

OpenStudy (anonymous):

oh okay i understand that

ganeshie8 (ganeshie8):

For our specific problem, it is easy to see that \(\rho\) varies from 0 to 1 because the radius of sphere is 1

ganeshie8 (ganeshie8):

Also \(\theta\) varies from 0 to 2pi is also trivial

ganeshie8 (ganeshie8):

you need to do some work to figure out the bounds for \(\phi\)

OpenStudy (anonymous):

is θ always 0 to 2pi?

ganeshie8 (ganeshie8):

It depends, from the diagram you can see that \(\theta\) is the angle in xy plane. \(\theta ~: ~0\to 2\pi\) means this angle is swept one full revolution

OpenStudy (anonymous):

2 full revolution would be 4pi?

ganeshie8 (ganeshie8):

You never want to do 2 full revolutions as that might duplicate the volume

ganeshie8 (ganeshie8):

btw you're correct about 4pi being two full revolutions

OpenStudy (anonymous):

oh okay so when finding the limits of ϕ what would i do

ganeshie8 (ganeshie8):

the part of sphere between z=1/2 and z=0 looks like below? |dw:1436649362434:dw|

OpenStudy (anonymous):

yeah i see that

ganeshie8 (ganeshie8):

z=0 represents the xy plane, whats the angle \(\phi\) for xy plane ?

ganeshie8 (ganeshie8):

Remember, \(\phi\) is the angle from z axis

OpenStudy (anonymous):

pi/3 to 0?

ganeshie8 (ganeshie8):

z axis is perpendicular to xy plane, yes ?

OpenStudy (anonymous):

yes

ganeshie8 (ganeshie8):

so whats the angle between xy plane and positive z axis ?

OpenStudy (anonymous):

its looks 60 degrees

OpenStudy (anonymous):

its not that ?

ganeshie8 (ganeshie8):

Easy, xy plane makes 90 degrees with the positive z axis.

ganeshie8 (ganeshie8):

|dw:1436649826870:dw|

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