Question

perform the addition.. How do I solve this? The answer I got was incorrect.

Answer 1

(-5+5i) + (9+8i)

Answer 2

4+13i

Answer 3

Yes I know that thats the correct answer. Im not asking for that. Im asking how to solve it

Answer 4

\[\left(5i-5\right)+\left(8i+9\right)\]
\[\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\]
\[=\left(5i-5\right)+8i+9\]
\[\mathrm{Add/Subtract\:the\:numbers:}\:-5+9=4\]
\[=8i+5i+4\]
\[\mathrm{Add\:similar\:elements:}\:8i+5i=13i\]
\[=13i+4\]
that is the answer

Answer 5

are you understand @Destinyyyy

Answer 6

Sorry one second while I read it.. There was a spider in my room :(

Answer 7

hahaha no problem @Destinyyyy

Answer 8

My example said to remove the i and put it outside of the equation..

(-5 +5) +(9+8)i

Answer 9

It was fluttering huge... Death by broom

Answer 10

it change f-ing to fluttering -.-

Answer 11

\[\mathrm{Simplify}\:\left(-5+5\right):\quad 0\]
\[=i\left(8+9\right)+0\]
\[\mathrm{Simplify}\:i\left(8+9\right):\quad 17i\]
17i+0=17i

Answer 12

The way your book does it is still true but i think its in this format

(a+bi) + (d+ ci) = (a+d) (b+c) i

Answer 13

To add or subtract we use
Add
(a+bi) + (c +di) = (a+b) + (c +d)i

Subtract
(a+bi) (c +di) = (a+b) - (c +d)i

So in your case
(-5+5i) + (9+8i) =
(-5+5) + (9+8)i
-5+9 + 5+8
4 + 13i

Answer 14

any confusion @Destinyyyy

Answer 15

@Deeezzzz -5+9=4
not -4

Answer 16

Okay.. I get it now.. I multiplied the parenthesis... Thank you everyone!!

Answer 17

Makes sense?

Answer 18

Yes.. Can I get help with another one?

Answer 19

yes tell me @Destinyyyy

Answer 20

Thanks! @DecentNabeel simple arithmetic mistake

Answer 21

no problem @Deeezzzz

Answer 22

Perform the addition

(-9/2 +1/2i) + (3/2 - 7/2i)

Answer 23

\[\left(-\frac{9}{2}+\frac{i}{2}\right)+\left(\frac{3}{2}-\frac{7i}{2}\right)\]
\[\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\]
\[=\left(-\frac{9}{2}+\frac{i}{2}\right)+\frac{3}{2}-\frac{7i}{2}\]
\[\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}\]
\[=\frac{-7i+i+3-9}{2}\]
refine
\[=\frac{-6i-6}{2}\]
factor out -6
\[=-\frac{6\left(i+1\right)}{2}\]
\[\mathrm{Divide\:the\:numbers:}\:\frac{6}{2}=3\]
\[=-\left(3\left(i+1\right)\right)\]
\[\mathrm{Negate}\:-\left(3\left(i+1\right)\right)=-3\left(i+1\right)\]
\[=-3\left(i+1\right)\]
that is the answer

Answer 24

ok @Destinyyyy

Answer 25

??? Why is the 1 now i and the 7 now 7i?

Answer 26

My examples show to put the i on the outside of the equation like @Nixy did

Answer 27

-3i+3

Answer 28

Still confused

Answer 29

why confused tell me

Answer 30

you said i on the out sides ..
so that..
3(i+1)
=3i+3

Answer 31

No I mean like this (-9/2 +1/2) + (3/2 - 7/2)i for the first step

Answer 32

\[\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\]
\[=\left(-\frac{9}{2}+\frac{i}{2}\right)+\frac{3}{2}-\frac{7i}{2}\]

Answer 33

alright @Destinyyyy

Answer 34

I dont understand why 1 is now i and why its 7i

Answer 35

ok i expla it

Answer 36

\( \huge (-\frac{9}{2} +\frac{1}{2}i) + (\frac{3}{2} - \frac{7}{2}i) \)

Is the above how it looks in your book?

Answer 37

(-9/2 +1/2i) + (3/2 - 7/2i)
that is your question

Answer 38

\( \huge (-\frac{9}{2} +\frac{1}{2}i) + (\frac{3}{2} - \frac{7}{2}i) \)

\( \huge (-\frac{9}{2} +\frac{1}{2}) + (\frac{3}{2} - \frac{7}{2}) i\)

\( \huge (-\frac{9}{2} +\frac{3}{2}) + (\frac{1}{2} - \frac{7}{2}) i\)

\( \huge -\frac{6}{2} + (-\frac{6}{2}) i\)

\( \huge -3 -3i\)