Question

help guys

Answer 1

statics

Answer 2

@Calcmathlete

Answer 3

@Calcmathlete

Answer 4

@abb0t

Answer 5

@abbot

Answer 6

@nincompoop

Answer 7

@nincompoop

Answer 8

@triciaal

Answer 9

@triciaal

Answer 10

@jim_thompson5910 please help I don't remember this stuff

Answer 11

help me please :(

Answer 12

@nincompoop will you please help?

Answer 13

@mathmate

Answer 14

@mathmate

Answer 15

@mathmate

Answer 16

@misssunshinexxoxo

Answer 17

i think i can help you but what is that 2N/m written in the blocks??

Answer 18

@rajat97 those are distributed loads. you multiply the force by the length of the distribution so you can treat it as a single force. Like the load between A and B is 2 N/m distributed over 3 m, so it's 6 N acting in the middle 1.5 m from either end.

I don't see a way to do this without setting up a long series of equations

Answer 19

Thanks a lot @peachpi

Answer 20

@kash_TheSmartGuy

Answer 21

@rajat97 @peachpi thank you so much :))

Answer 22

help me guys

Answer 23

@ganeshie8

Answer 24

@peachpi

Answer 25

@rajat97

Answer 26

i cant solve this stuff

Answer 27

help me please

Answer 28

i have the answer i don't know it is correct or wrong
normal reaction at K=4.571N
normal reaction at L=3N
normal reaction at M=9.5715N
normal reaction at N=8.1905N
please let me know if any of my answers are correct
if they are, i would be able to help you
I used only two concepts - newton's third law and rotational equilibrium

Answer 29

can you show it ?

Answer 30

@rajat97

Answer 31

@rajat97 ur answer is correct , how did you get that :((( , please help me with that :((

Answer 32

There is no system of equations to solve, you only have to resolve the reactions of each of the 7 beams, from top to bottom, and convert them to loads.
To find the reaction of the supports, you take moments about the other support, and solve for the reaction.
For example, for beam AB, length = 3 m, load = 2 N/m, so total load = 3 m * 2 N/m = 6 N. By symmetry, each support supports a load of 6/2=3 N, thus the load on support B is equivalent to 3 N.

Note that for calculation of reactions (external loads only), the uniform load can be replaced by an equivalent load equal to the total load (udl*length) applied at the middle of the uniform load. Remember that this should not be done when you are calculating the internal forces of the beam.
Now to tackle beam DC, you will make a load diagram, take moments about D and C, and check that the sum of reactions equal to the total load.