Simplify..
(4-3i)-(-8+i)
(4-(-8))+(-3-1)i
What are the like terms in this expression?
\(\large\color{black}{ \displaystyle (a-b)-(-c+d)}\) \(\large\color{black}{ \displaystyle a-b+c-d}\)
just doing it abstractly but with these signs, you should first go about this problem in a similar matter.
Huh?
And whether i is an imaginary number √(-1) , or just a variable like a,b, c and on... `you should expand the parenthesis and add like terms`
I know the answer is 12-4i But how?
You added the like terms.
Or, more creative (4-3i)-(-8+i) (12-8-3i)-(-8+i) (12-8-4i+i)-(-8+i) (12-4i-8+i)-(-8+i) (12-4i)+(-8+i)-(-8+i)
I assume 4+8= 12 and -3-1=-4 But my example (5-7i)-(9-9i) does it different
That ones is -4-2i 5+9 doesnt equal -4.. Please explain this
Its because it is 5-9=-4 not +
(5-(-9)) +(-7-1) two negatives turn into a positive--> (5+9) +(-7+1) @14mdaz
i thought you said it was (5-7i)-(9-9i), so when you expand it all out its 5-7i-9--9i=-4-2i
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