Let f(x) = 4x2 + x + 1 and g(x) = x2 – 2. Find g(f(x)). Show each step of your work. Help please
@marihelenh can you help me with this one too?
@freckles
You would replace what you have for f(x) into the x position of g(x). \[\left( 4x ^{2}+x+1 \right)^{2}-2\] Does that make sense?
but where does the x^2-2 go
the -2 is there but the x^2 i only see the ^2 added but not the x
The f(x) becomes a function of g(x), so you just replace what f was equal to into wherever the x is in the g equation.
oh i think i get it
yes i get it :D
Ok great! It is a little difficult trying to explain on here sometimes.
4x^4+x^3-1 would this be the final answer?
@marihelenh
Just one sec, let me check.
No, the answer is actually even longer.
To find the answer you would have to do, \[(4x ^{2}+x+1)(4x ^{2}+x+1) -2\]
This is so hard, i thought i understood but now i don't.
Do you have to simplify it?
It says Find g(f(x)) so I think I have to but maybe not
Well, if you don't have to, you already have your answer, but I will help you simplify it. Just hang in with me. It will seem confusing, but we will get through it and to the answer. OK?
ok, thank you
The first thing you should do, is multiply the first term of the first set by the second set. |dw:1436743172709:dw|
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