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A car cost $20,000 when it was purchased. The value of the car decreases by 8% each year. Find the rate of decay each month and select the correct answer below
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So yearly decay is *0.92^x (when x=year), per month would just be a 12th of that
\[P=20000\times 0.92^{\frac{ m }{ 12 }}\]
The decay depends on the current price not the original
im confused
−0.006924% −0.006667% −0.666667% −0.6924%
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those are the answer choices
Its B then :/ now im confused
oh wait its A
\[1-(0.92^{\frac{ 1 }{ 12 }})\]
=0.006924
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ohok i get it now. thank you
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