Question

1st ODE !

Answer 1

\[x'=(x-t)^2+1\]

Answer 2

This thing isn't liniar any ideas ?

Answer 3

Hmm I have an idea.. but it's not giving me the same solution as Wolfram..
So I'm thinking I made a boo boo somewhere.
I'll at least show you my attempt

Answer 4

Let \(\large\rm u=x-t\)
Differentiating our sub with respect to time gives
\(\large\rm u'=x'-1\qquad\to\qquad x'=u'+1\)
Subbing everything in gives us,\[\large\rm u'+1=(u)^2+1\]\[\large\rm u'=u^2\]And then just seperation, ya? :o

Answer 5

Ooo goodie! I actually am getting the same as wolfram, i just didn't simplify it far enough :)

Answer 6

Able to make sense of that? It should be correct :O

Answer 7

thx

Answer 8

Am I right @zepdrix ?