Question

y=-3(sec^2x - tan^2(x)) + 4x^3
I do not know how to solve this! Please help with the calc problem!! Thank you!

Answer 1

sec(x) = 1/cos(x)

Answer 2

recall Pythagorean identities
\[\sin^2(x)+\cos^2(x)=1 \\ \text{ divide both sides by } \cos^2(x) \\ \tan^2(x)+1=\sec^2(x) \\\]
anyways I don't know what it is meant by solve

Answer 3

could you say what solve means here @amyna if you are here

Answer 4

you say this is a cal problem
do you really mean differentiate
are you trying to find the inverse
like what are you doing exactly

Answer 5

yup sorry! differentiate it, thanks!

Answer 6

so you need help to differentiate -3+4x^3
just use constant rule and constant multiple rule and power rule?

Answer 7

-3 is a constant
the derivative of a constant is 0

Answer 8

\[\frac{d}{dx} cx^n \\ c \frac{d}{dx} x^n \text{ by constant multiple rule } \\ c n x^{n-1} \text{ by power rule }\]

Answer 9

\[\frac{d}{dx}(-3)=? \\ \frac{d}{dx}4x^3=?\]