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OpenStudy (anonymous):
yup! :)
OpenStudy (mertsj):
The 3 on the right side is supposed to be a 2
OpenStudy (mertsj):
\[x=-10\]
OpenStudy (mertsj):
Now. Is that extraneous or not? Does it cause any denominator to be 0? Does it make the original equation true?
OpenStudy (anonymous):
extraneous?
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OpenStudy (mertsj):
Why is it extraneous?
OpenStudy (anonymous):
3/ -5 +1/5 = 2/-5
OpenStudy (anonymous):
I don't know. When i plugged it in, that's the equation I got above,
OpenStudy (mertsj):
\[-\frac{3}{5}+\frac{1}{5}=-\frac{2}{5}\]
OpenStudy (mertsj):
Is that true or not?
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OpenStudy (mertsj):
Is any denominator equal to 0 ?
OpenStudy (anonymous):
no
OpenStudy (mertsj):
Then it is a perfectly fine solution and is not extraneous.
OpenStudy (anonymous):
Oh!
OpenStudy (anonymous):
Thank you:)
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OpenStudy (anonymous):
Can I ask one more?
OpenStudy (mertsj):
An extraneous solution is a number that appears to be a solution but doesn't hold up to scrutiny because it either doesn't check or causes a denominator to be 0.
OpenStudy (mertsj):
Yes
OpenStudy (anonymous):
Solve for x: 2 over 5 plus 3 over 5 x equals quantity x plus 5 over 10.
OpenStudy (anonymous):
Okay! I understand now:)
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