A toy rocket is launched straight up into the air with an initial velocity of 60 ft/s from a table 3 ft above the ground. If acceleration due to gravity is –16 ft/s2, approximately how many seconds after the launch will the toy rocket reach the ground?
~h(t) = at2 + vt + h0
A.0.05 s
B.2.03 s
C.3.80 s
D.3.70 s

Question

A toy rocket is launched straight up into the air with an initial velocity of 60 ft/s from a table 3 ft above the ground. If acceleration due to gravity is –16 ft/s2, approximately how many seconds after the launch will the toy rocket reach the ground?
~h(t) = at2 + vt + h0
A.0.05 s
B.2.03 s
C.3.80 s
D.3.70 s

anonymous · Answer

they don't give you much to work with here do they?

anonymous · Answer

your actual job is to solve 
$$-16t^2+60t+3=0$$ that is all

jim_thompson5910 · Answer

saying `acceleration due to gravity is –16 ft/s2` is false

the acceleration due to gravity is actually 32 ft/s^2

jim_thompson5910 · Answer

but the equation -16t^2 + 60t + 3 = 0 is correct

anonymous · Answer

thank you guys a lot!