Question

Please help! Picture included.

Answer 1

HI!!

Answer 2

the function changes at \(x=1\) right?

Answer 3

I have no idea :/ I'm really confused with what the questions are asking for Part 2 especially

Answer 4

erase the line to the left of \(x=1\) and erase the parabola to the right of \(x=1\)

Answer 5

Wait so just the entire left side?

Answer 6

your function is two different things right? one part is a parabola, the other is a line

Answer 7

it changes at 1

Answer 8

to the left of 1 it is a parabola
to the right of 1 it is a line

Answer 9

here is a nice picture
http://www.wolframalpha.com/widgets/view.jsp?id=5075763dba6ec763f31004272f8aa7fa

Answer 10

ok that didn't work, but you can fill it in for yourself to see what it should look like
i can't send it with fields filled out

Answer 11

wait let me take a picture with the erased parts bc i'm not sure if i erased it correctly

Answer 12

@misty1212

Answer 13

yeah good job!

Answer 14

yayy
that's c right?
how would i do d

Answer 15

closed circle goes on the parabola, because of the \(x\leq 1\) open circle on the line because of \(x>1\)

Answer 16

get rid of the arrows

Answer 17

do i put circles at the end of each line and parabola

Answer 18

oh okay thank you! :)

Answer 19

i don't put it on the other side?

Answer 20

nope

Answer 21

just at the break

Answer 22

okay thank you so much!!

Answer 23

\[\color\magenta\heartsuit\]

Answer 24

I'm going to add some information. So basically, we were given a piecewise function

\[x^2, x \leq 1 \]
this means that when our x is less than or equal to 1 we have to graph \[x^2 \]
since we we have \[\leq \] we draw a closed circle. This also applies when we have \[\geq \] ( we draw a closed circle)

\[2x+1, x > 1\]
this means that our x is greater than 1. So on the graph, we draw 2x+1 after x = 1
since we have > we draw an open circle. This also applies when we have < (we draw an open circle.
So our graph will look at this