Question

Please help!
Solve tan(x)(tan(x)-1)=0

Answer 1

\[\Large x = \pm n(\pi) \ , \ x = \frac{\pi}{4}\pm n(\pi) \]

Answer 2

Thank You so much!

Answer 3

tan(x)(tan(x) - 1) = 0


tan(x) = 0 or tan(x) - 1 = 0

tan(x) = 0 or tan(x) = 1

Solve tan(x) = 0 to get x = 0. Since we can add on multiples of pi, this means that we get x = ±n(pi) where n is any integer

Now solve tan(x) = 1 to get x = pi/4. Now add on multiples of pi to get x=pi/4±n(pi)


Note: in both cases, you're either using a calculator or the unit circle


Now combine the two solutions to get the final answer\[\Large x = \pm n(\pi) \ , \ x = \frac{\pi}{4}\pm n(\pi) \]

Answer 4

np

Answer 5

Solve on the interval \[[0,2\pi):\]
\[2\cos ^{2}x+3cosx+1=0\]