Question

Yelp!!!!

Answer 1

@IrishBoy123 help check my work please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

i tink i know my mistake!!!!

Answer 3

it should have been f3=5((346m/sec)/2(0.54m) )

Answer 4

never mind i take that back!!! that's for the closed harmonic!!! LOL :"D

Answer 5

f3=3((346m/sec)/2(0.54m) ) this is right...!!!

Answer 6

in a closed air column each harmonic occurs at 1 3 5 7 pattern where as the open doesn't

Answer 7

@IrishBoy123 are you there?!?!?!?!!?!? O-O

Answer 8

go back to basics and draw the wave shapes

starting from the given that v = const and v = \(f.\lambda\) we get v = \(f_n.\lambda_n\)

and, for the harmonics for an open air column:

\(L = \lambda_1/2 = 2\lambda_2/2=3\lambda_3/2 = 4\lambda_4/2 = \ ...n\lambda_n/2\)

for the 3rd harmonic, \(f_3 = v / \lambda_3 = \frac { v }{\frac{2L}{3}} = \frac{3v}{2L}\)

\(f_3 = \frac{3*346}{2*0.54} = 961Hz\)

Answer 9

harmonics for open ended go in halves:

http://hyperphysics.phy-astr.gsu.edu/hbase/waves/opecol.html#c3

everything else follows from that

Answer 10

LOL yah sorry i kinda confused my self but that's what i got!!!! :"D
i watched a really nice video on this topic and it did a great deal of help!!!!